If 32g of kerosine of density of 0.80g/centimeter cube are mixed with 8g of water. What is the density of the resulting vector
density = total mass / total volume
(32+8)g / (32/0.8 + 8)cm^3 = 40/48 = 5/6 g/cm^3
vector?
Density is =total/mass/total/volume (32+8)g(32/0.8+8)cm^3=40/48=5/6glcm^3
Density(Pm)= Mm/Vm
Mm= Mk + Mw
=32 + 8
= 40
Pk= Mk/Vk
Vk= Mk/Pk
=32/0.8
=40cm^3
Vw= Mw/Pw
= 8/1.0
=8cm^3
To find the density of the resulting mixture, we need to know the total volume of the mixture.
1. Start by finding the volume of kerosene:
- Given: Mass of kerosene = 32g
- Density of kerosene = 0.80g/cm^3
- Use the formula: Density = Mass / Volume
- Rearrange the formula to solve for volume: Volume = Mass / Density
- Volume of kerosene = 32g / 0.80g/cm^3 = 40 cm^3
2. Find the volume of water:
- Given: Mass of water = 8g (water's density is approximately 1g/cm^3, so we don't need to calculate it separately)
- Volume of water = Mass of water = 8cm^3
3. Calculate the total volume of the mixture:
- Total volume = Volume of kerosene + Volume of water = 40cm^3 + 8cm^3 = 48cm^3
4. Calculate the density of the resulting mixture:
- Given: Total mass = Mass of kerosene + Mass of water = 32g + 8g = 40g
- Density of the resulting mixture = Total mass / Total volume
- Density = 40g / 48cm^3 = 0.83g/cm^3 (rounded to two decimal places)
Therefore, the density of the resulting mixture is approximately 0.83g/cm^3.