What is the freezing point (in °C) of a solution with 60.6 g of NaCl dissolved in 1050 g of H₂O? Assume complete ionization.
dT = i*Kf*molality
i = 2 for NaCl
Kf = ?
molality = m = mols/kg solvent.
mols = grams/molar mas = about 60.6/18 = ?
You can calculate mols NaCl and you know kg solvent = 1.050, plug in i and Kf (assume you know that) and m and solve for delta T. Subtract from zero to find new freezing point.