Create an image representing an abstract concept of gas diffusion. It should include a visually appealing and clean scientific scenario featuring a porous pot in a controlled laboratory environment. The pot should contain a gas, represented by small particles, which are diffusing out into the larger environment. Please refrain from including any specific measurements, numerals, or text in the image.

400cm^3 of a gas x diffuse through a porous pot in 2 minutes. calculate the rate at which x diffuse

rate = volume/time (in secs)

V = 400cm3
t = 2mins => 2 x 60 =120s

rate = 400/120 = 3.33cm^3 s^-1

What is the exact answer

Rate=volume /time

Rate = 400/2×60
Rate = 400/120
= 3.33cms-¹

Do you want the rate in cc/min? cc/sec? L/?

rate = volume/time. 400 cc/2 min will give yu 200 cc/min
Change the time to seconds or hours or change 400 cc to L or gallons or whatever if you want something other than cc/min

Rate is in cm3 s^-1

I also do not know the answer someone please help find the answer

There are 60 seconds in a minute. Therefore, to convert the time from minutes to seconds, we have to multiply the number of minutes by 60.

Incorrect

400 centimetre cube is is divided by it's minutes

That is 100 cm cube / 2 minutes equals to 200 cm cube s -1

I really need the workings of this question am summitting it on friday