A golf ball and a bowling ball are dropped from the same height, which bounce and return to the same starting height. Which one experienced a greater impulse after they have interacted with the ground?

To determine which object experienced a greater impulse after interacting with the ground, we need to understand what impulse is and how it is calculated.

Impulse is defined as the change in momentum of an object. It is equal to the force applied to an object multiplied by the time over which the force is applied. Mathematically, impulse (J) is expressed as:

J = F * Δt

where F is the force applied to the object and Δt is the time interval during which the force acts.

In the case of the golf ball and the bowling ball, we can assume that both balls experience the same gravitational force since they are dropped from the same height. Therefore, the force acting on each ball is the same. However, the time of contact with the ground might be different for each ball due to their different properties and the bounce characteristics of the surfaces.

Typically, a golf ball is more elastic than a bowling ball, meaning it can retain more of its original shape and energy upon impact with the ground. A bowling ball, on the other hand, tends to be less elastic, causing more deformation and a larger loss of energy during impact.

Due to the increased deformation and energy loss in the bowling ball, the time interval during which the force is applied is longer, resulting in a smaller impulse compared to the golf ball. So, the golf ball will experience a greater impulse after interacting with the ground.

It is worth mentioning that this explanation is based on typical properties of golf balls and bowling balls. The specific materials, construction, and other factors can vary, potentially leading to different outcomes.

impulse is change of momentum. delta m V

if V is the same, then big m is big impulse

These are all very fundamental questions and you better understand them.