Each battery is a 1.5 V cell. If the current in circuit 2 is 3 amperes (3 A), what is the voltage drop across the light bulb for circuit 2?
To find the voltage drop across the light bulb in circuit 2, you need to use Ohm's Law, which states that the voltage (V) is equal to the current (I) multiplied by the resistance (R). In this case, the resistance of the light bulb needs to be known.
If the resistance of the light bulb is given in the problem, you can directly use Ohm's Law to calculate the voltage drop across the light bulb. The formula for Ohm's Law is V = I x R, where V represents voltage, I represents current, and R represents resistance.
However, if the resistance of the light bulb is not given, you would need more information to determine the exact voltage drop across the light bulb.
Let's assume that the resistance of the light bulb is known. If the current in circuit 2 is 3 amperes (3 A), and the resistance of the light bulb is, for example, 2 ohms (2 Ω), you can apply Ohm's Law.
V = I x R
V = 3 A x 2 Ω
V = 6 volts
In this case, the voltage drop across the light bulb in circuit 2 would be 6 volts.