A person is standing on a tower which is 5 m high from his eye sight and is looking at the ball down, the angle of depression is 18°. Find how far is the ball from the tower.
Tan18 = 5/x
X = 15.4 m.
Did you draw a diagram?
Now review your basic trig functions, and (if I parse your mangled lanugage correctly) you can see that the distance x from the tower can be found using
x/5 = tan 18°
Now the trig is done -- the rest is just Algebra I
dang - saved by henry2
To find the distance between the ball and the tower, we can use trigonometry and the angle of depression.
Let's denote the distance between the ball and the tower as "x".
We can form a right triangle with the tower, the ball, and the person's line of sight. The vertical leg of the triangle represents the height of the tower (5 m), and the horizontal leg represents the distance between the ball and the tower (x).
Using the angle of depression (18°), we can determine the tangent of the angle. In this case, the tangent is equal to the opposite side (5 m) divided by the adjacent side (x):
Tan(18°) = 5 m / x
Now, we can solve for x by isolating it:
x = 5 m / Tan(18°)
Using a scientific calculator or trigonometric table, we can find the value of the tangent of 18°, which is approximately 0.3249.
Therefore, the distance between the ball and the tower (x) is:
x ≈ 5 m / 0.3249 ≈ 15.381 m
Hence, the ball is approximately 15.381 meters away from the tower.