A number has more tens than hundreds or ones.what would be the number?
one such number would be 121
I'm sure you can think of many more.
193 ?
I am sure that is uniquely it :)
No ideas
To find a number that has more tens than hundreds or ones, we can try different combinations of digits. Let's break down the conditions given:
1. The number has more tens than hundreds or ones.
This means that the tens digit is greater than both the hundreds and ones digits.
2. The number has a higher tens digit compared to the hundreds and ones digits.
This implies that the tens digit is the largest of the three.
Based on these conditions, we can systematically try different combinations until we find a suitable number. Let's start:
1. Start with the largest possible tens digit: 9.
2. For the hundreds digit, use a smaller number, let's say 1.
3. For the ones digit, use a smaller number again, let's say 0.
Now, we have the number 910. This number has a tens digit (1) greater than the hundreds digit (0) and ones digit (0). Therefore, 910 is a number that fulfills the given conditions.