# Science

A 20 kg block rests on a rough horizontal table. A rope is attached to the block and is pulled with a force of 80 N to the left. As a result, the block accelerates at 2.5 m/s2. The coefficient of kinetic friction μk between the block and the table is ___ .( Round the answer to the nearest hundredth.)
This is big boi stuff!

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1. 20 kg * 2.5 m/s^2 = 50 N

so the frictional force is ... 80 N - 50 N = 30 N

Ff = m * g * μk

μk = 30 N / (20 kg * 9.8 m/s^2) = 30 N / 196 N

the coefficient of friction is just a number ... no units

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2. What is the answer rounded to the nearest hundred?

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3. calculator broken??

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