A force of 0.8 n stretches an elastic wire by 2cm determine the elastic constant of the material
F = kx
Now plug in your numbers.
k = F/d = 0.8N./0.02m = 40N/m.
To determine the elastic constant of a material, you need to use Hooke's Law, which states that the force applied to an elastic material is directly proportional to the extension produced, as long as the material is not stretched beyond its elastic limit.
Hooke's Law can be expressed as:
F = k * x
Where:
F is the force applied
k is the elastic constant (also known as the spring constant or stiffness constant)
x is the extension produced
In this case, we are given that a force of 0.8 N (Newton) stretches the elastic wire by 2 cm (centimeters).
To find the elastic constant (k), we need to rearrange the equation:
k = F / x
Substituting the given values:
k = 0.8 N / 2 cm
Since the unit of force should be in Newton (N) and the unit of extension should be in meters (m) for the correct result, we need to convert centimeters (cm) to meters (m) by dividing by 100:
k = 0.8 N / (2 cm / 100)
k = 0.8 N / 0.02 m
Evaluating the equation:
k = 40 N/m
Therefore, the elastic constant (or spring constant) of the material is 40 N/m.