A force of 0.8n stretches spring by 20m.find the elastic constant of the spring
I think you have a typo or that is the bungie cord I have on the doorknob to practice rowing while stuck at home. Anyway:
F = k x
k = Force in Newtons / distance in METERS
To find the elastic constant of the spring, we need to use Hooke's Law equation, which states that the force exerted by a spring is directly proportional to the amount it is stretched or compressed.
The formula for Hooke's Law is:
F = k * x
Where:
F is the force applied to the spring (0.8 N in this case),
k is the elastic constant (what we need to find),
x is the displacement or stretch of the spring (20 m in this case).
Rearranging the formula to solve for the elastic constant (k), we get:
k = F / x
Plugging in the values we have:
k = 0.8 N / 20 m
Simplifying the equation:
k = 0.04 N/m
Therefore, the elastic constant of the spring is 0.04 N/m.
To find the elastic constant of a spring, also known as the spring constant or k, you need to use Hooke's Law. Hooke's Law states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.
The formula to calculate the spring constant is:
k = F / x
Where:
k = spring constant (elastic constant)
F = force applied to the spring
x = displacement (change in length) of the spring
Given:
Force, F = 0.8 N
Displacement, x = 20 m
Using the formula, we can calculate the elastic constant of the spring:
k = 0.8 N / 20 m
Dividing the force by the displacement, we get:
k = 0.04 N/m
Therefore, the elastic constant of the spring is 0.04 N/m.