A hydrometer of mass 24g floats with 6cm of its stem above oil of density 0.8g/km cubic. The area of cross sectioned area of the stem is 0.75cm square. Calculate...
(A)mass of oil displaced
(B) Volume of
To calculate the mass of oil displaced, we need to determine the volume of the part of the hydrometer submerged in the oil.
First, let's find the volume of the submerged part of the hydrometer's stem. We know the length of the submerged part is 6cm, and the cross-sectional area is 0.75cm². So:
Volume of submerged part = length × cross-sectional area
= 6cm × 0.75cm²
= 4.5 cm³
Since 1 cm³ is equal to 1 mL, the volume of the submerged part is also 4.5 mL.
Now we can calculate the mass of the oil displaced. We can use the formula:
Mass = Volume × Density
The density of the oil is given as 0.8 g/cm³.
Mass of oil displaced = Volume of submerged part × Density of oil
= 4.5 cm³ × 0.8 g/cm³
= 3.6 g
Therefore, the mass of oil displaced is 3.6 g.
Now, let's calculate the volume of the oil displaced.
We already know that the volume of the submerged part of the hydrometer is 4.5 cm³.
Thus, the volume of oil displaced is equal to the volume of the submerged part of the hydrometer, which is 4.5 cm³.
Therefore, the volume of the oil displaced is 4.5 cm³.