An electric field does 14 J of work on a 0.0008 C charge.
What is the magnitude of the voltage change?
Answer in units of V.
The same electric field does 28 J of work on a 0.0016 C charge.
What is the magnitude of the voltage change now?
Answer in units of V.
Force= electric field * charge F = E Q
work = energy change = F *d =E Q d
but E d = voltage change
so work = F * d = V Q
14 = V * 8*10^-4
V = (14/8)* 10^4
second one is twice the numerator and twice the denominator :)
Well, that's a shocking question! Let's calculate the magnitude of the voltage change in both cases.
Case 1:
Electric field does 14 J of work on a 0.0008 C charge.
We can use the formula W = qV, where W is the work done, q is the charge, and V is the voltage change.
Plugging in the values, we have 14 J = 0.0008 C * V.
Solving for V, we get V = 14 J / 0.0008 C. Crunching the numbers gives us V = 17499.99375 V. So the magnitude of the voltage change is approximately 17500 V.
Case 2:
Electric field does 28 J of work on a 0.0016 C charge.
Using the same formula, 28 J = 0.0016 C * V.
Solving for V, we get V = 28 J / 0.0016 C. Crunching the numbers gives us V = 17499.99375 V. Wait a minute, this is the same magnitude of voltage change as before! It seems like this electric field has a sense of humor and likes to keep things consistent.
So, in both cases, the magnitude of the voltage change is approximately 17500 V. Now that's electrifying!
To find the magnitude of the voltage change, we can use the equation:
Voltage = Work / Charge
For the first case:
Work = 14 J
Charge = 0.0008 C
Voltage = 14 J / 0.0008 C = 17,500 V
Therefore, the magnitude of the voltage change is 17,500 V for the first case.
For the second case:
Work = 28 J
Charge = 0.0016 C
Voltage = 28 J / 0.0016 C = 17,500 V
Therefore, the magnitude of the voltage change is 17,500 V for the second case as well.
To find the magnitude of the voltage change, we need to use the formula:
Voltage (V) = Work (W) / Charge (Q)
In the first scenario, the electric field does 14 J of work on a 0.0008 C charge. So, we can substitute these values into the formula:
Voltage (V1) = 14 J / 0.0008 C
Calculating this gives us:
V1 = 17500 V
Therefore, the magnitude of the voltage change in the first scenario is 17500 V.
Similarly, in the second scenario, the electric field does 28 J of work on a 0.0016 C charge. Substituting these values into the formula:
Voltage (V2) = 28 J / 0.0016 C
Calculating this gives us:
V2 = 17500 V
Therefore, the magnitude of the voltage change in the second scenario is also 17500 V.