Which of the following ordered pairs is a solution of the equation y = -4x(square)?
Oh yea and..
A. (-2, 16)
B. (1, -8)
C. (0, -4)
D. (2, -16)
Please explain
To determine which of the given ordered pairs is a solution of the equation y = -4x^2, we can substitute the values of x and y into the equation and check if the equation holds true.
Let's consider each of the given ordered pairs:
1) (-1, 4):
Substituting x = -1 and y = 4 into the equation:
4 = -4(-1)^2
4 = -4(1)
4 = -4
The equation does not hold true, so (-1, 4) is not a solution.
2) (0, 0):
Substituting x = 0 and y = 0 into the equation:
0 = -4(0)^2
0 = -4(0)
0 = 0
The equation holds true, so (0, 0) is a solution.
3) (2, -16):
Substituting x = 2 and y = -16 into the equation:
-16 = -4(2)^2
-16 = -4(4)
-16 = -16
The equation holds true, so (2, -16) is a solution.
Therefore, the ordered pairs that are solutions of the equation y = -4x^2 are (0, 0) and (2, -16).
To determine which of the given ordered pairs is a solution of the equation y = -4x^2, we need to substitute the x- and y-values of each pair into the equation and see if the equation holds true.
Let's go through each ordered pair one by one:
1) (-1, 4)
Substituting x = -1 and y = 4 into the equation: 4 = -4(-1)^2
Simplifying the equation: 4 = -4(1) or 4 = -4
This equation is not true, so (-1, 4) is not a solution.
2) (0, 0)
Substituting x = 0 and y = 0 into the equation: 0 = -4(0)^2
Simplifying the equation: 0 = 0
This equation is true, so (0, 0) is a solution.
3) (2, -16)
Substituting x = 2 and y = -16 into the equation: -16 = -4(2)^2
Simplifying the equation: -16 = -4(4) or -16 = -16
This equation is true, so (2, -16) is a solution.
In summary, the ordered pairs (0, 0) and (2, -16) are solutions of the equation y = -4x^2.