An urn contains white and green balls. Six balls are randomly drawn from the urn in succession, with replacement. That is, after each draw, the selected ball is returned to the urn. What is the probability that all balls drawn from the urn are white? Round your answer to three decimal places.
well, it will be P(white)^6
now use the numbers of balls, which you omitted.
To find the probability of drawing all white balls, we need to determine the probability of drawing a white ball in each individual draw. Since the selected ball is replaced after each draw, the probability of drawing a white ball remains the same throughout the process.
Let's assume that the urn contains a total of n balls, out of which w are white and g are green. In this case, we are not given the total number of balls or the breakdown of white and green balls. So, we cannot determine the exact probability without this information.
However, we can still provide a general formula to calculate the probability. Let's say the probability of drawing a white ball in one draw is p. Since the draws are independent events, the probability of drawing all white balls in six successive draws with replacement would be:
P(all white balls) = p * p * p * p * p * p = p^6
Again, without knowing the values of n, w, and g, we cannot calculate the exact probability. If you have that information, please provide it, and I'll be happy to help you calculate the probability.