Use triangle ABC to write the value of tanA as a ratio.
Triangle A B C has segment A B that measures 45 units, B C is 28 units, and A C measures 53. Angle B is a right angle.
What is the ratio for tanA?
Enter your answer as a fraction in simplest form, like this: 42/53
TanA = BC/AB.
So it's 28/45?
Yeah the answer is 28/45
To find the value of tanA, we can use the tangent ratio, which is defined as the ratio of the length of the side opposite the angle to the length of the side adjacent to the angle.
In triangle ABC, angle A is the angle we are interested in. The side opposite angle A is side AC, and the side adjacent to angle A is side AB. Given that AC measures 53 units and AB measures 45 units, we can write the ratio for tanA as:
tanA = opposite/adjacent = AC/AB = 53/45
To simplify this fraction, we can find the greatest common divisor (GCD) of 53 and 45, which is 1 in this case. Dividing both numbers by their GCD, we get:
tanA = 53/45
So, the ratio for tanA in simplest form is 53/45.