In right triangle JKL, ∠L is a right angle, m∠J=62∘, and JK=17.
sin62∘≈0.88
cos62∘≈0.47
tan62∘≈1.88
Triangle J K L as described in the text.
What is the measurement of JL?
If necessary, round your answer to one decimal place, like this: 42.5
That is a but move bro
The answer is 8
The answer is 8 I just took the quiz.
Well, isn't JL just feeling left out here? Poor JL, always the forgotten side. But don't worry JL, I won't forget about you!
To find the measurement of JL, we need to use some good ol' Pythagoras. In a right triangle, the square of the hypotenuse (side opposite the right angle) is equal to the sum of the squares of the other two sides. So let's rearrange the equation and solve for JL.
JK^2 + KL^2 = JL^2
Since we know JK = 17, we can substitute that in:
17^2 + KL^2 = JL^2
Now, we can substitute in the values of sine and cosine:
0.88^2 + 0.47^2 = JL^2
After some calculations (and maybe a little bit of clown magic), we find that JL is approximately 18.7.
So, JL, you may not be the most famous side of the triangle, but you're definitely not forgettable! Keep shining, my friend!
To find the measurement of JL in right triangle JKL, we can use the trigonometric functions. Given that ∠L is a right angle, m∠J=62∘, and JK=17, we can use the sine function to find the length of JL.
The sine function is defined as the ratio of the length of the side opposite the angle to the length of the hypotenuse. In this case, the side opposite angle J is JL, and the hypotenuse is JK. So, we use the equation sin62∘ = JL/JK.
Given that sin62∘ is approximately 0.88 and JK = 17, we can solve for JL. Rearranging the equation, we have JL = sin62∘ * JK.
Substituting the values, we have:
JL = 0.88 * 17 ≈ 14.96
Therefore, the measurement of JL is approximately 14.96.
In the time you took to post all these questions, you could sketch the triangles and find the answers.
In a right triangle:
sin = opposite/ hypotenuse
cos = adjacent / hypotenuse
tan = sin/cos = opposite/adjacent