A single, standard number cube is tossed. What is the probability of getting a 4 or a 5?
A. 1
B. 1/5
C. 1/3
D 1/6
1/3?
So there is 6 sides (and 6 numbers). 4 and 5 are two numbers so, they are 2/6 sides. 2/6 = ? (simplify it to lowest terms)
Yes.
Exploring Probability Unit Test Connexus 6th grade
1. C ; 1/3
2. A ; 1/8
3. B ; 3/10
4. B ; 1/3
5. A ; 0.32
6. B ; 7/8
7. B ; 10 times
8. B ; 168 people
9. C; 300 telephones
10. B ; 2/9
11. D ; 60 choices
12. D ; 1/12
13. C ; You draw two colored pencils without replacement and get get one red and one yellow
14. D ; 1/12
15. All the different combinations are: fish and spinach, fish and broccoli, fish and carrots, chicken and spinach, chicken and broccoli, chicken and carrots, beef and spinach, beef and broccoli, beef and carrots.
The probability of getting a 4 or a 5 is the sum of the probabilities of getting a 4 and getting a 5, because these two events are mutually exclusive (you cannot get both a 4 and a 5 on the same roll).
Each number on a standard number cube is equally likely to come up, so there are 6 possible outcomes, each with a probability of 1/6.
Therefore, the probability of getting a 4 is 1/6, and the probability of getting a 5 is also 1/6.
The probability of getting a 4 or a 5 is the sum of these two probabilities:
1/6 + 1/6 = 2/6 = 1/3
So the probability of getting a 4 or a 5 is 1/3.
To find the probability that a shopper selected at random from the 50 surveyed prefers red or blue, you need to add the number of shoppers who prefer red to the number of shoppers who prefer blue, and then divide by the total number of shoppers surveyed.
Looking at the table provided would help us to extract the following information:
- 10 shoppers prefer red
- 15 shoppers prefer blue
Therefore, the total number of shoppers who prefer red or blue is:
10 + 15 = 25
The probability of selecting a shopper at random who prefers red or blue is therefore:
25/50 = 0.5 or 50%
So the probability that one shopper, selected randomly from the 50 surveyed, preferred the color red or blue is 50%.
The probability of rolling an even number on a number cube is 3/6, or 1/2, since there are three even numbers (2, 4, and 6) out of six possible outcomes. The probability of not rolling a 2 on a number cube is 5/6, since there are five numbers (1, 3, 4, 5, and 6) out of six possible outcomes that are not 2.
To find the probability of rolling an even number on the first roll and not rolling a 2 on the second roll, we need to multiply the probabilities of each event.
P(even, then not 2) = (1/2) x (5/6)
Simplifying,
P(even, then not 2) = 5/12
So the probability of rolling an even number on the first roll and not rolling a 2 on the second roll is 5/12.
There are 12 letters in the mix, and only 2 of them are A's. Therefore, the probability of drawing an A is:
a. P(A) = 2/12
Simplifying the fraction,
P(A) = 1
Help me, please. I think D?
I don't know, HELP!!!