at the moment when a shot putter releases a 5 kg shot, the shot is 3 m above the ground and travelling at 15 m/s. it reaches a maximum height of 14.5 m above the ground and then falls to the ground. if air resistance is negligible, what was the potential energy of the shot as it left the hand relative to the ground?

Question

at the moment when a shot putter releases a 5 kg shot, the shot is 3 m above the ground and travelling at 15 m/s. it reaches a maximum height of 14.5 m above the ground and then falls to the ground. if air resistance is negligible, what was the potential energy of the shot as it left the hand relative to the ground?

Answer 1

unless this is a trick question,

PE = mgh
as usual, right?

Answer 2

To find the potential energy of the shot as it left the hand relative to the ground, we can use the concept of gravitational potential energy.

Gravitational potential energy is given by the formula:

Potential Energy = mass * g * height

where:
mass = 5 kg (mass of the shot)
g = 9.8 m/s^2 (acceleration due to gravity)
height = 3 m (initial height of the shot)

Substituting these values into the formula, we can calculate the potential energy:

Potential Energy = 5 kg * 9.8 m/s^2 * 3 m
Potential Energy = 147 J

Therefore, the potential energy of the shot as it left the hand relative to the ground was 147 Joules.

Answer 3

To calculate the potential energy of the shot as it left the hand relative to the ground, we need to determine the potential energy at its maximum height. The potential energy of an object is given by the equation:

Potential Energy = mass × gravity × height

Given:
Mass of the shot (m) = 5 kg
Height when released (h1) = 3 m (above ground)
Maximum height (h2) = 14.5 m (above ground)
Gravity (g) = 9.8 m/s² (acceleration due to gravity)

First, let's calculate the potential energy when the shot was released:

Potential Energy1 = mass × gravity × height1
Potential Energy1 = 5 kg × 9.8 m/s² × 3 m
Potential Energy1 = 147 joules

Now, let's calculate the potential energy at the maximum height:

Potential Energy2 = mass × gravity × height2
Potential Energy2 = 5 kg × 9.8 m/s² × 14.5 m
Potential Energy2 = 713.5 joules

Since potential energy is dependent on an object's position, the potential energy at the maximum height is the maximum potential energy reached by the shot.

Therefore, the potential energy of the shot as it left the hand relative to the ground is 147 joules.

Porco dio

unless this is a trick question,

To find the potential energy of the shot as it left the hand relative to the ground, we can use the concept of gravitational potential energy.

To calculate the potential energy of the shot as it left the hand relative to the ground, we need to determine the potential energy at its maximum height. The potential energy of an object is given by the equation: