Buses to Aintree leave the station every 25 minutes.
Buses to Blossford leave the station every 30 minutes.
Buses to both places leave at 8am.
What is the next time buses to Aintree and Blossford leave the station together?
the answer is 10:30 am
8am + 150
150 is the smallest number divisible by both 25 and 30
8 am + 150 min = ?
To find the next time buses to Aintree and Blossford leave the station together, we need to find the least common multiple (LCM) of 25 minutes and 30 minutes.
The LCM of 25 and 30 is 150, which means they will leave the station together every 150 minutes.
Since the buses leave at 8am, the next time they will leave together is 150 minutes after 8am.
Therefore, the next time buses to Aintree and Blossford leave the station together is at 8:00am + 150 minutes = 10:30am.
To find out the next time buses to Aintree and Blossford leave the station together, we need to find the least common multiple (LCM) of 25 minutes and 30 minutes. The LCM is the smallest multiple that both 25 and 30 divide into evenly.
To find the LCM, we can use the prime factorization method:
The prime factors of 25 are 5 x 5.
The prime factors of 30 are 2 x 3 x 5.
To calculate the LCM, we need to take all the prime factors of both numbers, including common factors, and multiply them together:
LCM = 2 x 3 x 5 x 5 = 150
So, the next time buses to Aintree and Blossford leave the station together is in 150 minutes or 2 hours and 30 minutes from 8 am.
Thus, the next time buses to Aintree and Blossford leave the station together is at 10:30 am.