Also, can someone set this problem up into equations so i can solve.thanks

A plane took 1 hour longer to travel 560 miles on the first portion of a flight than it took to fly 480 miles on the second portion. If the speed was the same for each portion, what was the flying time for the second part of the trip?

One way (v in miles per hour)

Using distance/speed=time

(560/v)+ 1=480/v

find v

then find 480/v for time taken for second part of trip.

I THOUGHT IT WAS

R = D/T

Yes, velocity =distance/time

so time = distance/velocity

NOW HOW DO I CHANGE THIS INTO HOURS.

FOR THIS PROBLEM I GOT FOR T= 4.6 FOR THE SECOND PART

AND 5.6 FIRST PART

To convert the time into hours, you need to consider the units you are using. Since you have distances in miles and speeds in miles per hour, the resulting time will be in hours.

In your equation, time = distance/velocity, you correctly identified the equation for time. Let's go through the steps using your given values.

For the first part of the trip:
Distance = 560 miles
Time = 5.6 hours (converted from 1 hour longer)

For the second part of the trip:
Distance = 480 miles
Time = ? (to be determined)

Using the equation time = distance/velocity, let's find the velocity (speed) first.

For the first part:
5.6 hours = 560 miles / velocity
Rearranging the equation to solve for velocity, we get:
velocity = 560 miles / 5.6 hours
velocity = 100 miles per hour

Now that we have the speed, we can determine the time for the second part of the trip.

For the second part:
480 miles = 100 miles per hour * time
Rearranging the equation to solve for time, we get:
time = 480 miles / 100 miles per hour
time = 4.8 hours

So, the flying time for the second part of the trip is 4.8 hours.