How do you find the wavelength of the fourth harmonic of a closed pipe with length 2m?
closed at one end, or the other? It matters. If it is closed at one end, then this is a clue: https://qph.fs.quoracdn.net/main-qimg-716de8fa533ef3121e56125cc6221d36
To find the wavelength of the fourth harmonic of a closed pipe with length 2m, you need to use the formula:
λ = 4L / n
where λ is the wavelength, L is the length of the pipe, and n is the harmonic number.
In this case, we have L = 2m and n = 4. Plugging these values into the formula, we can calculate the wavelength:
λ = 4(2m) / 4
= 8m / 4
= 2m
Therefore, the wavelength of the fourth harmonic of a closed pipe with a length of 2m is 2m.