Four resistors of resistance 1ohm,2ohms,3ohms,5 ohms are connected in series and afterwards in parallel. Calculate the combined resistance in each case.
This is one of the most basic setups. Clearly you need to do some reading.
series: R = 1+2+3+5 = 11
parallel:
1/R = 1/1 + 1/2 + 1/3 + 1/4
R = 12/25
a. R = 1+2+3+5 = 11 ohms.
b. 1/R = 1/1+1/2+1/3+1/5 = 2.033
R = 0.0492 ohms.
31 of May,2021
R=R1+R2+R3+R4
R=1+2+3+5= 11ohms
1/R=1/R1+1/R2+1/R3+1/R4
1/R=1/1+1/2+1/3+1/5
1/R=60/31
cross multiply
R=31/60
R=0.49ohms.
(In series)R=R1+R2+R3+R4
R=1+2+3+5
R=11ohms
(In parallel)1/R=1/R1+1/R2+1/R3+1/R4
1/R=1/1+1/2+1/3+1/5
Finding LCM(30)
1/R=61/30
Crosss multiplying
61R=30
Dividing by 61 to get R
R=30/61
R=0.4918 or 0.492ohms