12.5g of zinc trioxo carbonate(iv), ZnCo3, were heated to a constant mass and the residue treated with excess hydrochloric acid. Calculate the mass of zinc chloride that will be produced (Zn =65 C=12 O=16 H=1 Cl=35
Pls I don't understand can you please put the answer in full
Note that your name for ZnCO3 is not an approved name by IUPAC.
ZnCO3 + heat ==> ZnO + CO2
ZnO + 2HCl ==> ZnCl2 + H2O
mols ZnCO3 initially = grams/molar mass = approx 0.1
Convert that to mols ZnCl2 formed this way.
0.1 mol ZnCO3 x (1 mol ZnO/1 mol ZnCO3) x (1 mol ZnCl2/1 mol ZnO) = 0.1 mol ZnCl2.
grams ZnCl2 = mols ZnCl2 x molar mass ZnCl2 = ?
Post your work if you get stuck.
To determine the mass of zinc chloride produced, we need to understand the chemical reaction that occurs when zinc trioxo carbonate (ZnCO3) reacts with hydrochloric acid (HCl). The balanced equation for this reaction is:
ZnCO3 + 2HCl -> ZnCl2 + H2O + CO2
According to the equation, 1 mole of ZnCO3 reacts with 2 moles of HCl to produce 1 mole of ZnCl2. Therefore, we need to calculate the number of moles of ZnCO3 present in 12.5g.
First, we calculate the molar mass of ZnCO3:
Zinc (Zn): 1 atom * 65 g/mol = 65 g/mol
Carbon (C): 1 atom * 12 g/mol = 12 g/mol
Oxygen (O): 3 atoms * 16 g/mol = 48 g/mol
Total molar mass of ZnCO3: 65 + 12 + 48 = 125 g/mol
Next, we calculate the number of moles of ZnCO3:
moles = mass / molar mass
moles = 12.5g / 125 g/mol = 0.1 mol
From the balanced equation, we know that 1 mole of ZnCO3 produces 1 mole of ZnCl2. Therefore, the mass of ZnCl2 produced will be equal to the molar mass of ZnCl2 multiplied by the number of moles of ZnCO3:
Molar mass of ZnCl2: Zn (65 g/mol) + Cl2 (2 * 35 g/mol) = 65 + 70 = 135 g/mol
Mass of ZnCl2 = molar mass * moles = 135 g/mol * 0.1 mol = 13.5 g
Therefore, the mass of zinc chloride produced will be 13.5 grams.
To calculate the mass of zinc chloride that will be produced, we first need to determine the molar mass of zinc trioxo carbonate (ZnCO3).
The molar mass of zinc (Zn) is 65 g/mol.
The molar mass of carbon (C) is 12 g/mol.
The molar mass of oxygen (O) is 16 g/mol.
The molar mass of ZnCO3 can be calculated as follows:
Zn = 65 g/mol
C = 12 g/mol
O = 16 g/mol (there are three oxygen atoms, so we multiply by 3)
Molar mass of ZnCO3 = (65 g/mol) + (12 g/mol) + (3 * 16 g/mol) = 161 g/mol
Now, we can calculate the number of moles of ZnCO3 in 12.5 grams using the formula:
Number of moles = mass / molar mass
Number of moles of ZnCO3 = 12.5 g / 161 g/mol = 0.07764 mol (rounded to 5 decimal places)
Since the stoichiometry of the reaction tells us that one mole of ZnCO3 reacts with two moles of HCl to produce one mole of zinc chloride (ZnCl2), we can use this information to find the number of moles of zinc chloride produced.
Number of moles of ZnCl2 = Number of moles of ZnCO3 / 2 = 0.07764 mol / 2 = 0.03882 mol (rounded to 5 decimal places)
Finally, to find the mass of zinc chloride produced, we use its molar mass.
Molar mass of ZnCl2 = (65 g/mol) + (2 * 35 g/mol) = 135 g/mol
Mass of zinc chloride = Number of moles of ZnCl2 * Molar mass of ZnCl2
= 0.03882 mol * 135 g/mol = 5.24 grams (rounded to 2 decimal places)
Therefore, the mass of zinc chloride produced is approximately 5.24 grams.