Mr. McGregor stands on top of a 15 m high cliff. He fires his rifle horizontally. The bullet speed is 321 m/s. How far from the cliff did the bullet travel?
how long does it take to fall 15m?
multiply that time * speed to get distance
0.5*g*T^2 = 15.
0.5*9.8*T^2 = 15
T =
d = V*T.
To solve this problem, we need to use the formula for horizontal projectile motion:
distance = speed × time
In this case, the speed is the bullet's initial velocity, which is given as 321 m/s. However, we don't have the time the bullet was in motion.
To find the time, we need to determine how long it took for the bullet to hit the ground. Since the bullet was fired horizontally, its vertical motion is due to gravity. We can use the equation:
height = (1/2) × gravity × time^2
In this equation, the height is the initial height of Mr. McGregor, which is 15 m, and gravity is approximately 9.8 m/s^2. We solve this equation to find the time it takes for the bullet to reach the ground.
15 = (1/2) × 9.8 × time^2
Simplifying the equation, we get:
15 = 4.9 × time^2
Divide both sides by 4.9:
3 = time^2
Taking the square root of both sides yields:
time = √3 ≈ 1.73 seconds
Now that we have the time, we can use the formula for distance to find how far the bullet traveled horizontally:
distance = speed × time
distance = 321 m/s × 1.73 s
distance ≈ 555.33 meters
Therefore, the bullet traveled approximately 555.33 meters horizontally from the cliff.