Set up the Discriminant

2x^2+12x+10
A) (square root of) 122-4(2)(10)
B) (square root of) 22-4(12)(10)
C) (square root of) 12-4(2)(10)
D) 122-4(2)(10)
Can someone help, I am really confused.

Ok thank you so much

To set up the discriminant for a quadratic equation in the form of ax^2 + bx + c, you can use the formula:

Discriminant = b^2 - 4ac

In this case, the given quadratic equation is 2x^2 + 12x + 10.

So, a = 2, b = 12, and c = 10.

Now we can substitute these values into the discriminant formula:

Discriminant = (12)^2 - 4(2)(10)

Simplifying the equation:

Discriminant = 144 - 80
Discriminant = 64

So, the discriminant of the equation 2x^2 + 12x + 10 is 64.

Comparing this result with the given options, we can see that the correct answer is missing. None of the options match the calculated discriminant of 64.

The discriminant is

b^2 - 4ac
= 12^2 - 4(2)(10) =