Algebra

9. Solve the system of equations algebraically. Show all work. (2 pts.)
y = -x2 + 4x – 3
y = -x + 1
I have tried everything before coming here, but I'm still stuck.

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  1. since y = -x + 1 and y = -x^2 + 4x – 3 are both equal to y, you can set them opposite to each other because they are both equal

    you then get
    -x+1 = -x2 + 4x – 3

    if you multiply both sides by -1, you get
    x-1 = x^2 - 4x + 3

    after moving everything to one side, you get
    0 = x^2 - 5x + 4

    after that, it's just a matter of factoring
    0 = (x-1)(x-4)

    we get x = 1, and x = 4

    If you plug both of these x values into the equation, you come up with y = 0 for x = 1, and y = -3 for x = 4

    you answers are (0,1) and (-3,4)

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  2. It’s

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  3. You and u get 69

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