4. Which equation has (2, −1) as a solution? (1 point)
y = 2x − 1
y = x + 3
y = x – 3
y = −2x + 1
did you try substituting the given point into each equation?
I'll try the last equation, you do the others
for (2, −1)
LS = -1
RS = −2(2) + 1
= -4+1 = -3 ≠ LS
I guess that's not the one, ....
To find the equation with the solution (2, -1), we need to substitute the values of x = 2 and y = -1 into each of the given equations to see which equation satisfies these values.
Let's substitute the values into each of the equations:
1. For y = 2x - 1:
y = 2(2) - 1
y = 4 - 1
y = 3
2. For y = x + 3:
y = 2 + 3
y = 5
3. For y = x - 3:
y = 2 - 3
y = -1
4. For y = -2x + 1:
y = -2(2) + 1
y = -4 + 1
y = -3
From the above calculations, we can see that the only equation that satisfies the values (2, -1) is y = x - 3. So, the correct equation is y = x - 3.