y=2x^2-2x-3x+3 y=2x^2-5x+3 0=2x^2-3x-2 when you minus this u get y=-2x-3x+5 how is this possible
y=2x^2-2x-3x+3 --> y = 2x^2 - 5x + 3 , so the first two are the same equation.
0 = 2x^2 - 3x - 2
are you subtracting this equation from the first?
then:
y-0 = 2x^2 - 2x^2 - 5x -(-3x) + 3-(-2)
y = -2x + 5
Why dint you multiply 2x^2 *-2x^2 as you have done with the others
At no point did I multiply anything
2x^2 - 2x^2 = 0 , that was a subtraction, just like 5-5 = 0
To understand how you arrived at the expression y=-2x-3x+5, let's break down the process step by step.
First, we have the given equations:
1. y = 2x^2 - 2x - 3x + 3
2. y = 2x^2 - 5x + 3
To simplify these equations, we can combine like terms. In the first equation, the terms -2x and -3x can be combined:
y = 2x^2 - 5x + 3
Now, the equation can be rearranged to match the form 0 = ax^2 + bx + c. To do this, we subtract y from both sides of the equation:
0 = 2x^2 - 5x + 3 - y
Since we have two expressions for y (equations 1 and 2), we can substitute y with 2x^2 - 2x - 3x + 3 in the equation above:
0 = 2x^2 - 5x + 3 - (2x^2 - 2x - 3x + 3)
Expanding the expression within the parentheses, we get:
0 = 2x^2 - 5x + 3 - 2x^2 + 2x + 3x - 3
Now, we can combine like terms:
0 = -5x + 2x + 3x + 3 - 3
Combining further:
0 = -3x + x
Finally, we can simplify the equation:
0 = -2x
Dividing both sides by -2, we get:
0 = x
Hence, the correct equation we obtain from subtracting the equation 0 = 2x^2 - 3x - 2 is simply x = 0. It seems there was an error in your calculations, as y = -2x - 3x + 5 is not a valid conclusion based on the given equations.