Solve the following automotive-services problem.
In first gear, or low gear, an automobile's engine runs about three times as fast as the drive shaft. In second gear, the engine does not have to run as fast; usually it runs about 1.6 times faster than the drive shaft. Finally, in third, or high gear, the engine runs at the same speed as the drive shaft.
Engine speed = 3,500 r.p.m.
Transmission in first gear
Drive-shaft speed (to nearest r.p.m.) = _______ r.p.m.
To find the drive-shaft speed in first gear, we can use the given information that the engine runs about three times as fast as the drive shaft.
Engine speed = 3,500 r.p.m.
Drive-shaft speed in first gear = Engine speed / 3
Substituting the given values, we have:
Drive-shaft speed in first gear = 3,500 / 3
Drive-shaft speed in first gear ≈ 1,166.67 r.p.m.
Therefore, the drive-shaft speed in first gear is approximately 1,166.67 r.p.m.
To solve this automotive-services problem, we need to find the drive-shaft speed of an automobile in first gear.
Given information:
Engine speed = 3,500 r.p.m.
Transmission in first gear
Engine runs about three times as fast as the drive shaft in first gear.
To find the drive-shaft speed, we can use the following formula:
Drive-shaft speed = Engine speed / Gear ratio
Since the engine in first gear runs about three times as fast as the drive shaft, the gear ratio is 1:3. Therefore, the gear ratio is 1/3.
Using the formula and given information, we can calculate the drive-shaft speed:
Drive-shaft speed = 3,500 r.p.m. / (1/3)
Drive-shaft speed = 3,500 r.p.m. * (3/1)
Drive-shaft speed = 10,500 r.p.m.
Therefore, the drive-shaft speed, to the nearest r.p.m., is 10,500 r.p.m.