A(aq) + 2 B(aq) ⟶ 4 C(aq) + 4 D(aq)
What is the rate of production of C, in mol L−1 s−1, if the rate of production of D is 0.310 mol L−1 s−1 ?
Wouldn't that be 0.310 mol L−1 s−1 ?
thats what i thought, thanks!
To find the rate of production of C, we need to examine the stoichiometry of the balanced chemical equation given.
From the equation, we can see that for every 4 moles of C produced, we also produce 4 moles of D. Therefore, the rate of production of C is the same as the rate of production of D.
Given that the rate of production of D is 0.310 mol L−1 s−1, the rate of production of C would also be 0.310 mol L−1 s−1.
Hence, the rate of production of C is 0.310 mol L−1 s−1.