When Antonio opens and lays a cereal box out flat, he sees that the top and the bottom of the box each measure 2 inches by 7 inches, the sides of the box each measure 2 inches by 12 inches, and the front and back of the box each measure 7 inches by 12 inches. What is the surface area of Antonio's cereal box
The result of laying out a box like that is called a net.
you will see 3 pairs of sides,
2 of a 2 by 7
2 of a 2 by 12
2 of a 7 by 12
find the area of each, and add them up
let me know what you got, and I will check your answer
As = (2*7)*2 + (2*12)*2 + (7*12)*2 = ----sq. in.
To find the surface area of Antonio's cereal box, we need to calculate the area of each individual face and then add them together.
Let's start by identifying the six faces of the cereal box:
1. Top face: This face measures 2 inches by 7 inches, so its area is 2 inches * 7 inches = 14 square inches.
2. Bottom face: This face is identical to the top face, measuring 2 inches by 7 inches, so its area is also 14 square inches.
3. Side faces (two of them): Each side face measures 2 inches by 12 inches, so the area of each side face is 2 inches * 12 inches = 24 square inches. Since there are two side faces, the total area of both side faces is 24 square inches * 2 = 48 square inches.
4. Front face: This face measures 7 inches by 12 inches, so its area is 7 inches * 12 inches = 84 square inches.
5. Back face: Like the front face, the back face also measures 7 inches by 12 inches, so its area is also 84 square inches.
Now, let's add up the areas of all the faces to find the total surface area:
14 square inches (top face) + 14 square inches (bottom face) + 48 square inches (two side faces) + 84 square inches (front face) + 84 square inches (back face) = 244 square inches.
Therefore, the surface area of Antonio's cereal box is 244 square inches.