Find the value of the greater root of x2 + 14x + 45 = 0.
A) -9
B) -5
C) 5
D) 9
Thank you Damon! It was D)
well,D is greater in magnitude but is more negative :)
x^2+14x+45 = 0. 45 = 9*5. 9+5 = 14 = B.
(x+9)(x+5) = 0
x+9 = 0. X = -9.
x+5 = 0. X =
To find the value of the greater root of the quadratic equation x^2 + 14x + 45 = 0, we can use the quadratic formula.
The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the roots can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In our case, we have a = 1, b = 14, and c = 45.
Plugging these values into the quadratic formula, we get:
x = (-14 ± √(14^2 - 4 * 1 * 45)) / (2 * 1)
x = (-14 ± √(196 - 180)) / 2
x = (-14 ± √16) / 2
Now, simplifying further:
x = (-14 ± 4) / 2
We have two possible solutions:
x1 = (-14 + 4) / 2 = -10 / 2 = -5
x2 = (-14 - 4) / 2 = -18 / 2 = -9
Therefore, the greater root is x = -5.
So, the answer is option B) -5.
[ -14 +/- sqrt( 196 - 180) ] /2
[ -14 + 4 ]/ 2 for the plus one
-10/2