A spiral spring natural length is 1.5m is extended by a force of 0.8N. What will be it's length when the applied force is 3.2N
No idea. How far did the 0.8N extend it?
we can say that the 3.2N force extends it 4 times as far, though, right?
Yes
To find the change in length of the spiral spring, we can use Hooke's law, which states that the force applied on a spring is directly proportional to the extension or compression of the spring.
Hooke's law formula is given by:
F = k * x
Where:
F = force applied on the spring
k = spring constant
x = change in length of the spring
In this case, we have two different forces and the corresponding lengths. We can set up a ratio using Hooke's law to find the new length.
First, let's rearrange the formula to solve for x:
x = F / k
We know that the natural length of the spring (when no force is applied) is 1.5m. Therefore, the force and length can be expressed as follows:
Force_1 = 0.8N
Length_1 = 1.5m
Using Hooke's law, we can find the spring constant:
k = Force_1 / Length_1
Now, we have k, Force_2, and we need to find Length_2.
Plugging in the values into the formula:
x = Force_2 / k
x = 3.2N / (Force_1 / Length_1)
x = 3.2N / (0.8N / 1.5m)
x = 3.2N / 0.533N/m
x ≈ 6.01m
Therefore, the length of the spiral spring when the applied force is 3.2N will be approximately 6.01m.