in any complex resistance circuit the voltage across any resistor in the circuit is always _________
equal or less than the voltage source or is it just less than the voltage source?
I would say less than or equal, depending on just what you mean by a "complex" resistance circuit.
If the resistor in question is in parallel with all the other resistances, then the voltage drop will be equal to the source, right?
In any complex resistance circuit, the voltage across any resistor is always less than or equal to the voltage source. Let me explain how to understand this concept.
In a complex resistance circuit, you have various resistors connected together and connected to a voltage source. When current flows through the circuit, a voltage drop occurs across each resistor according to Ohm's Law (V = I * R), where V is the voltage across the resistor, I is the current flowing through it, and R is the resistance of the resistor.
The total voltage supplied by the source is distributed across the resistors based on their individual resistance values. In series circuits, the voltage across each resistor adds up to the total voltage supplied by the source. In parallel circuits, the voltage across each resistor is the same and is equal to the voltage source.
However, regardless of the circuit configuration, the voltage across any individual resistor will always be less than or equal to the voltage source. This is because some of the voltage is consumed as it passes through the resistors. The sum of the voltage drops across all the resistors equals the total voltage supplied by the source.
So, in summary, the voltage across any resistor in a complex resistance circuit is always less than or equal to the voltage source.