the symbol for acceleration is a and the symbol for time is t
if a = 23t^2 and t is ≥ 0, then what is t?
sure looks that way to me but it is a strange question
t^2 = a/23
t = + sqrt(a) /sqrt 23 = sqrt a / 4.7958
thanks! so final answer is t = sqrt(a) divided by 4.7958?
To find the value of t given the equation a = 23t^2, we need to isolate t.
The equation can be rewritten as 23t^2 = a.
To isolate t, divide both sides of the equation by 23:
(23t^2) / 23 = a / 23.
Simplifying, we get:
t^2 = a / 23.
To solve for t, we need to take the square root of both sides of the equation.
√(t^2) = √(a / 23).
Since t can be either positive or negative, we have two possible solutions for t.
Therefore, the solution for t is ± √(a / 23).