2KClO3 → 2KCl + 3O2
How many moles of oxygen are produced if 4 moles of potassium chlorate decomposes?
4?
The balanced equation for the decomposition of potassium chlorate (KClO3) is:
2KClO3 → 2KCl + 3O2
According to the equation, for every 2 moles of potassium chlorate that decompose, 3 moles of oxygen are produced.
Therefore, if 4 moles of potassium chlorate decompose, we can set up a proportion to determine how many moles of oxygen are produced:
(4 moles KClO3) / (2 moles KClO3) = (x moles O2) / (3 moles O2)
Simplifying the proportion, we get:
2 = (x moles O2) / 3
Cross multiplying:
2 * 3 = x moles O2
6 = x moles O2
So, if 4 moles of potassium chlorate decompose, 6 moles of oxygen are produced.
To determine the number of moles of oxygen produced when 4 moles of potassium chlorate decomposes, we can use the stoichiometry of the balanced chemical equation you provided.
The balanced equation shows that 2 moles of potassium chlorate decompose to produce 3 moles of oxygen. So, the ratio of moles of oxygen to moles of potassium chlorate is 3:2.
To find the number of moles of oxygen produced, we can set up a proportion:
(3 moles of oxygen) / (2 moles of potassium chlorate) = X moles of oxygen / 4 moles of potassium chlorate
Cross-multiplying and solving for X gives us:
X = (3 moles of oxygen / 2 moles of potassium chlorate) * 4 moles of potassium chlorate
X = 6 moles of oxygen
Therefore, when 4 moles of potassium chlorate decompose, 6 moles of oxygen are produced.
2KClO₃ ---> 2KCl + 3O₂
2 mol 2 mol 3 mol
When 2 mol of KClO₃ decompose, 3 mol of oxygen are produced.