Calculate the moles of NH3 produced when 0.75 moles of N2 react.
first step: what is the reaction equation?
That will give you the ratio of moles in input and output.
N2 + 3H2 ==> 2NH3
0.75 mols N2 x (2 mols NH3/1 mol H2) = ?
Help me
To calculate the moles of NH3 produced when 0.75 moles of N2 react, we need to determine the balanced chemical equation for the reaction involving N2 and NH3.
The balanced chemical equation for the reaction is:
N2 + 3H2 -> 2NH3
From this balanced equation, we can see that every 1 mole of N2 reacts to produce 2 moles of NH3.
So, if we have 0.75 moles of N2, we can set up a simple proportion to determine the moles of NH3 produced.
0.75 moles N2 / 1 * 2 / 1 = 1.5 moles NH3
Therefore, when 0.75 moles of N2 reacts, we would produce 1.5 moles of NH3.