Find the product
1. (2x)(10x)
A: 20x
B:12x
C: 20x^2
D 5x
2. -3m(m+8)
A:-3m^2+24
B:-3m^2-24m
C:-24m^2
D:-4m+5
My answers: 1=a, 2=b
(Having more trouble with 2 but I dont know if 1 is right)
Theres two more questions but I'm gonna try to do them without help
2 is correct ... distributed the 3m over the binomial
for 1 ... it's all multiplication ... 2 * x * 10 * x
To find the product (2x)(10x), you can use the distributive property of multiplication over addition. This property states that for any real numbers a, b, and c, the product of a and the sum of b and c is equal to the sum of the products of a and b and a and c. In other words:
(a)(b + c) = (a)(b) + (a)(c)
Applying this property to the given expression, we have:
(2x)(10x) = (2x)(10) + (2x)(x)
Now, let's simplify each term separately:
(2x)(10) = 20x
(2x)(x) = 2x^2
Combining these terms, we get:
(2x)(10x) = 20x + 2x^2
Thus, the correct answer for the first question is C: 20x^2.
For the second question, (-3m)(m + 8), we can again use the distributive property:
(-3m)(m + 8) = (-3m)(m) + (-3m)(8)
Simplifying each term:
(-3m)(m) = -3m^2
(-3m)(8) = -24m
Combining these, we have:
(-3m)(m + 8) = -3m^2 - 24m
Hence, the correct answer for the second question is B: -3m^2 - 24m.
Please note that your answers are correct. Well done!