Which of the following gases at STP would have the greatest volume?
a] 1 mole of O ˇ2
b] 4 moles of He
c] 0.2 moles of SO ˇ3
d] 5 moles of H ˇ2
To determine which gas would have the greatest volume at STP, we need to compare the number of moles of each gas.
Given:
a) 1 mole of O2
b) 4 moles of He
c) 0.2 moles of SO3
d) 5 moles of H2
Using Avogadro's Law, which states that equal volumes of gases at the same temperature and pressure contain an equal number of molecules, we know that the gas with the highest number of moles will occupy the greatest volume.
Comparing the number of moles:
a) 1 mole of O2
b) 4 moles of He
c) 0.2 moles of SO3
d) 5 moles of H2
Therefore, the gas with the greatest volume at STP is option d) 5 moles of H2.
To determine which gas at STP (Standard Temperature and Pressure) would have the greatest volume, we need to consider the ideal gas law.
The ideal gas law is given by the equation:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
At STP, the pressure is 1 atmosphere (atm) and the temperature is 0 degrees Celsius (273.15 Kelvin).
Using the ideal gas law, we can rearrange the equation to solve for volume (V):
V = (nRT) / P
Now, we can calculate the volumes for each option:
a) 1 mole of O2:
V = (1 mole * 0.0821 L.atm/mol.K * 273.15 K) / 1 atm
V ≈ 22.4 L
b) 4 moles of He:
V = (4 moles * 0.0821 L.atm/mol.K * 273.15 K) / 1 atm
V ≈ 89.6 L
c) 0.2 moles of SO3:
V = (0.2 moles * 0.0821 L.atm/mol.K * 273.15 K) / 1 atm
V ≈ 4.48 L
d) 5 moles of H2:
V = (5 moles * 0.0821 L.atm/mol.K * 273.15 K) / 1 atm
V ≈ 112 L
Comparing the volumes calculated for each option, we can see that the gas with the greatest volume at STP is:
d) 5 moles of H2 with a volume of approximately 112 liters.
Therefore, option d) has the highest volume among the given gases at STP.