if one mole of the compound AL4C3 has a mass of 144g and mole of carbon has a mass of 12g, calculate the relative atomic mass of the element aluminium
any ideas to the answer would be great thanks
4*(Al, amu)+ 3*12 = 144
Solve for "Al,amu", the atomic mass of Al
To calculate the relative atomic mass of the element aluminum (Al), you need to find the atomic mass of Al, denoted as "Al, amu" in the given equation.
The equation provided for the compound AL4C3 tells us that one mole of AL4C3 has a mass of 144 grams. It also states that one mole of carbon (C) has a mass of 12 grams. The coefficient of aluminum (Al) in the formula is 4, indicating that there are four Al atoms in one mole of AL4C3.
Using this information, we can set up the mass equation:
4*(Al, amu) + 3*12 = 144
Now, solve for "Al, amu" by rearranging the equation and isolating the atomic mass of aluminum:
4*(Al, amu) = 144 - 3*12
4*(Al, amu) = 144 - 36
4*(Al, amu) = 108
Divide both sides of the equation by 4:
(Al, amu) = 108/4
(Al, amu) = 27
Therefore, the relative atomic mass of aluminum is 27 atomic mass units (amu).