A train travelling at 18 m/s accelerates uniformly at 2 m/s² for 6 seconds. Calculate the final speed of the train

well, think about it

The speed increases by 2 m/s every second

To calculate the final speed of the train, we can use the formula:

final speed = initial speed + (acceleration * time)

We are given:
Initial speed (u) = 18 m/s
Acceleration (a) = 2 m/s²
Time (t) = 6 seconds

Plugging in the values into the formula, we have:

final speed = 18 m/s + (2 m/s² * 6 s)
final speed = 18 m/s + 12 m/s
final speed = 30 m/s

Therefore, the final speed of the train is 30 m/s.

To calculate the final speed of the train, we can use the formula:

Final speed (v) = Initial speed (u) + (Acceleration (a) × Time (t))

Given:
Initial speed (u) = 18 m/s
Acceleration (a) = 2 m/s²
Time (t) = 6 seconds

Substituting the given values into the formula:

Final speed (v) = 18 m/s + (2 m/s² × 6 seconds)

Now, we can compute:

Final speed (v) = 18 m/s + (2 m/s² × 6 seconds)
= 18 m/s + (12 m/s)
= 30 m/s

Therefore, the final speed of the train is 30 m/s.

V = Vo + a*T = 16 + 2*6 =