What is the volume of 98.27 g of ammonia at STP
how many moles?
1 mole = 22.4 L
To find the volume of a gas at STP (Standard Temperature and Pressure), you can use the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
At STP, the pressure is 1 atm and the temperature is 273.15 K.
To find the number of moles, we can use the molar mass of ammonia (NH3), which is 17.03 g/mol.
First, we calculate the number of moles:
moles = mass / molar mass
moles = 98.27 g / 17.03 g/mol
moles ≈ 5.77 mol
Now, we can substitute the values into the ideal gas law equation:
PV = nRT
(1 atm) * V = (5.77 mol) * (0.0821 L·atm/(mol·K)) * (273.15 K)
Simplifying the equation, we get:
V ≈ (5.77 mol) * (0.0821 L·atm/(mol·K)) * (273.15 K) / (1 atm)
V ≈ 125.56 L
So, the volume of 98.27 g of ammonia at STP is approximately 125.56 liters.