What is the distance between the points (-7,3) and (4,-5) on a coordinate plane?
d^2 = (4+7)^2 + (-5-3)^2 = 185
d =
To find the distance between two points on a coordinate plane, you can use the distance formula. The formula is as follows:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
In this case, the points are (-7, 3) and (4, -5). Let's label them as (x1, y1) and (x2, y2) respectively.
x1 = -7, y1 = 3
x2 = 4, y2 = -5
Now let's substitute these values into the distance formula:
d = sqrt((4 - (-7))^2 + (-5 - 3)^2)
= sqrt((4 + 7)^2 + (-5 - 3)^2)
= sqrt(11^2 + (-8)^2)
= sqrt(121 + 64)
= sqrt(185)
Therefore, the distance between the points (-7, 3) and (4, -5) is sqrt(185), which is approximately 13.60.
To find the distance between two points on a coordinate plane, we can use the distance formula. The distance formula states that the distance between two points (x1, y1) and (x2, y2) is given by the formula:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
In this case, we have the points (-7, 3) and (4, -5). To find the distance between these points, we substitute the coordinates into the distance formula:
d = sqrt((4 - (-7))^2 + (-5 - 3)^2)
Simplifying inside the square root:
d = sqrt((4 + 7)^2 + (-5 - 3)^2)
d = sqrt(11^2 + (-8)^2)
d = sqrt(121 + 64)
d = sqrt(185)
Thus, the distance between the points (-7, 3) and (4, -5) on the coordinate plane is sqrt(185) units.