Well, I now need help with math as well..
What exclusions are placed on the variable x for the fraction: 4x^2-1/4x+2 ?
No, I need to know what exclusions are placed on the variable x.
A.) -1/2
B.) 0
C.) -1
D.) None
well that wasn't the answer anyways so Thanks :)
it was actually -1/2, and that's what I put.
To find the exclusions placed on the variable x in the fraction (4x^2-1)/(4x+2), we need to identify any values of x that would result in division by zero. Division by zero is undefined in mathematics.
In this case, we have a fraction where the denominator is 4x + 2. To identify any exclusions, we need to set the denominator equal to zero and solve for x.
4x + 2 = 0
To solve for x, we can subtract 2 from both sides:
4x = -2
Finally, divide both sides by 4:
x = -2/4
Simplifying further, we have:
x = -1/2
So, -1/2 is the value that would make the denominator 4x + 2 equal to zero in the fraction. Hence, x = -1/2 is excluded from the domain of the given fraction.
4x^2-1/4x+2
I am sure you meant:
(4x^2-1)/(4x+2)
= (2x+1)(2x-1)/(2(2x+1))
= (2x-1)/2 , oops I just divided by zero if x is equal to what value???