Two kids sit on a seesaw of length 4.2m, balanced at its center. Sarah sits at the for end and has a mass of 50.kg. The Anna is 75kg. They seesaw for a while (having a grand time) then decide to balance themselves. Then Sarah is given a bag of oranges weighing 3.0kg. and the seesaw rotates out of balance, When the Anna is given a bag of apples, balance is still not restored. She has to place the apples 0.33m behind her for them to be balanced again. What is the weight of the bog of apples?
I need help with this question please!!!
well, first find where Anna was.
50*2.1=75x so x= anna position frm center, x=2/3 * 2.1=4.2/2=1.4m frm center
next:
(50+3)*2.1=75*1.4 + M(1.4+.330
solve for mass of apples M.
What do you mean by C?
To solve this problem, we need to understand the concept of torque and balance.
First, let's define torque. Torque is the rotational equivalent of force - it is the product of the force applied and the distance from the axis of rotation. In this case, the axis of rotation is the center of the seesaw.
To balance the seesaw, the torques on both sides of the seesaw must be equal. The torque on one side of the seesaw is the product of the mass, the acceleration due to gravity (9.8 m/s^2), and the distance from the center of the seesaw to the point where the mass is located.
Let's calculate the torques on both sides of the seesaw when Sarah is on it.
Torque on Sarah's side: Torque_s = mass_s * gravity * distance
Given: mass_s = 50 kg, gravity = 9.8 m/s^2, and distance = 4.2 m / 2 = 2.1 m (since the seesaw is balanced at its center)
Torque_s = 50 kg * 9.8 m/s^2 * 2.1 m = 1029 Nm
Since the seesaw is balanced, the torque on Anna's side should be equal to the torque on Sarah's side.
Torque on Anna's side: Torque_a = mass_a * gravity * distance
Given: Torque_a = Torque_s = 1029 Nm, mass_a = 75 kg, and distance = 2.1 m
Now, we need to find the weight of the bag of apples (mass_apples) that is 0.33 m behind Anna.
Torque of the apples: Torque_apples = mass_apples * gravity * distance
Given: Torque_apples = Torque_s = 1029 Nm, distance = 0.33 m
1029 Nm = mass_apples * 9.8 m/s^2 * 0.33 m
Solving for mass_apples:
mass_apples = 1029 Nm / (9.8 m/s^2 * 0.33 m) = 1029 N / 3.234 N/kg
mass_apples ≈ 318.15 kg
Therefore, the weight of the bag of apples is approximately 318.15 kg.