Is the answer 3 Mr oobleck? What is the coefficient of x in the division (18^3+12x^2-3x)/6x^2
yes, 3. I assume you meant ((18x^3+12x^2-3x)/6x^2
Yes that's what I meant. Thank you so much!!!!
To find the coefficient of x in the division, let's simplify the division first.
We have:
(18^3 + 12x^2 - 3x) / 6x^2
To simplify this expression, you can divide each term of the numerator by the denominator:
18^3 / 6x^2 + 12x^2 / 6x^2 - 3x / 6x^2
Now, let's simplify each term:
18^3 / 6x^2 simplifies to (18 * 18 * 18) / (2 * 3 * x * x)
12x^2 / 6x^2 simplifies to 2
3x / 6x^2 simplifies to 1 / (2x)
Combining these simplified terms, we get:
(18 * 18 * 18) / (2 * 3 * x * x) + 2 - 1 / (2x)
Let's focus on the term that contains x: 1 / (2x).
The coefficient of x in this term is the number right before x, which is 1/2.
So, the coefficient of x in the division (18^3 + 12x^2 - 3x) / 6x^2 is 1/2 or 0.5.
Therefore, the answer is not 3.