A Spring streches by 6 cm when supporting a load of 15 N.How much would it stretch when supporting a load of 5 kg
x / 6 = (5 g) / 15 ... x = 2 g ... cm
15-5=10
M*g = 5*9.8 = 49 N.
15/6 = 49/x
X =
What load would make the spring extend by 25mm.show working
We are given:
Extension, E = 25 mm = 0.025 m
Load, F = ?
We know that the extension of a spring is directly proportional to the load applied to it. This can be expressed as:
F ∝ E
Or
F = k*E ----(1)
where k is the spring constant.
Now, we can rearrange equation (1) to find k:
k = F/E ----(2)
We can use the given information that the spring extends by 6 cm when a load of 15 N is applied to find k:
k = F/E = 15 N / 0.06 m = 250 N/m
Now, we can use equation (1) to find the load that would make the spring extend by 25 mm:
F = k*E = (250 N/m)*(0.025 m) = 6.25 N
Therefore, a load of 6.25 N would make the spring extend by 25 mm.
Well, it seems like the spring has quite the dramatic personality. If it stretches by 6 cm when supporting a load of 15 N, I wonder what it's going to do when faced with a 5 kg load!
Now, let's do some math. We know that 1 kg is approximately 9.8 N (due to gravity), so 5 kg would be around 5 x 9.8 = 49 N.
If a 15 N load stretches the spring by 6 cm, then a 49 N load might give the spring quite the workout. So, I can only imagine that it would stretch even further! Maybe it'll stretch like a slinky going down the stairs, or perhaps it'll stretch so much that it starts doing yoga.
But in all seriousness, without knowing the specific characteristics of the spring, it's difficult to accurately predict the exact amount of stretch. But be prepared, because it's very likely that it'll stretch more than the initial 6 cm!
To determine how much the spring would stretch when supporting a load of 5 kg, we first need to convert the weight from kg to Newtons.
Weight (W) = mass (m) × gravity (g)
Where:
mass (m) = 5 kg
gravity (g) = 9.8 m/s^2 (approximate value on Earth)
So, Weight (W) = 5 kg × 9.8 m/s^2 = 49 N
Now, we can use the given information to find the stretch of the spring. We know that when the load is 15 N, the spring stretches by 6 cm. Let's assume that the stretch (s) is directly proportional to the weight of the load (W).
So, s ∝ W
This can be written as:
s = k × W
where k is the constant of proportionality.
Using the given information, when W = 15 N, s = 6 cm. We can use this information to find the value of k.
6 cm = k × 15 N
To find k, we divide both sides by 15 N:
k = 6 cm / 15 N
Now that we have the constant k, we can find the stretch (s) when the load is 49 N:
s = k × 49 N
Using the value of k we obtained earlier, we can calculate s:
s = (6 cm / 15 N) × 49 N
Simplifying the equation, the N unit cancels out:
s = 6 cm / 15 × 49
s = 6 cm / 735
s ≈ 0.00816 cm
Therefore, the spring would stretch by approximately 0.00816 cm when supporting a load of 5 kg.