The toxicity level of a lake is found by dividing the amount of dissolved toxins the lake water currently has per liter by the maximum safe amount of dissolved toxins that the water can hold per liter and then converting it to a percentage. If the river currently has 0.86 milligrams of dissolved toxins per liter of water and the maximum safe amount of dissolved toxins is 1.04 milligrams per liter, what is the toxicity level of the lake water, to the nearest percentage?
A. 86%
B. 84%
C. 83%
D. 80%
E. 79%
C. 83%
The methodology for determining the correct answer appears to be elucidated in the first sentence that you typed.
To find the toxicity level of the lake water, we need to calculate the ratio of dissolved toxins to the maximum safe amount of dissolved toxins and then convert it to a percentage.
The ratio of dissolved toxins to the maximum safe amount of dissolved toxins is calculated by dividing the amount of dissolved toxins (0.86 milligrams) by the maximum safe amount of dissolved toxins (1.04 milligrams):
0.86 / 1.04 ≈ 0.827
To convert this ratio to a percentage, we multiply it by 100:
0.827 * 100 ≈ 82.7%
Rounding to the nearest percentage, the toxicity level of the lake water is approximately 83%.
Therefore, the answer is C. 83%.
To calculate the toxicity level of the lake water, we need to divide the amount of dissolved toxins the lake water currently has per liter by the maximum safe amount of dissolved toxins that the water can hold per liter.
First, let's calculate the toxicity level by dividing the current amount of dissolved toxins (0.86 milligrams) by the maximum safe amount of dissolved toxins (1.04 milligrams):
Toxicity level = (0.86 milligrams / 1.04 milligrams) * 100%
Dividing the values, we get:
Toxicity level = 0.8269230769230769 * 100%
Rounding the toxicity level to the nearest percentage, we get:
Toxicity level ≈ 82.7%
Therefore, the toxicity level of the lake water, to the nearest percentage, is approximately 83%.
So, the correct answer is C. 83%.