When a number is squared it is equal to that number times 5. What is a possible solution
well, you have x*x = x*5
what do you think?
Can u pls explain
c'mon, guy, if x*5 = x*x then x must be 5, right?
or, if you want to go around the long way,
x^2 = 5x
x^2-5x = 0
x(x-5) = 0
so, either x=0 or x-5 = 0
That is, x = 0 or x=5
To find a possible solution for this problem, we need to set up an equation based on the given information. Let's assume the number we're looking for is represented by the variable 'x'.
The first piece of information states that when a number is squared, it is equal to that number times 5. Mathematically, we can write this as: x^2 = 5x.
To find a possible solution, we will solve this equation.
Step 1: Rearrange the equation to bring all the terms to one side: x^2 - 5x = 0.
Step 2: Factor out the common factor, which is 'x': x(x - 5) = 0.
Step 3: Apply the zero-product property, which states that if the product of two factors is zero, then at least one of the factors must be zero. So, either x = 0 or (x - 5) = 0.
Step 4: Solve for 'x' in each case:
- For x = 0, we have one possible solution, which is 'x = 0'.
- For (x - 5) = 0, we solve for 'x' and find another possible solution, which is 'x = 5'.
Therefore, the possible solutions to the equation x^2 = 5x are x = 0 and x = 5.