A figure is composed of a semicircle and a right triangle. Determine the area of the shaded region. Use 3.14 for π and round to the nearest tenth. Show all of your work.
(semicircle then the right triangle with 5 ft on the top and 4 ft on the bottom of the triangle)

I'm having trouble with this one. I need help figuring out how to solve this

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  1. If I am seeing the shape correctly the 4 and 5 are the legs of the triangle then you need to use the Pythagorean Theorem c^2 = 5^2 + 4^2 to find the length of the hypotenuse of the triangle (which is the diameter of the semi-circle).
    But perhaps without a diagram I am missing something ??

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    Ms Pi 3.14159265358979323
  2. I would show the diagram if I could but there's a line that goes straight up and another line that goes down at an angle (5 ft) and then the bottom that connects the two (4 ft). I describes it as best as I could so would I still use that same theorem?

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  3. Assuming we have a 3-4-5 rt. triangle. radius = 4/2 = 2.
    A1 = (bh)/2 = (4*3)/2 = 6 Ft^2 = area of triangle.
    A2 = shaded area.
    A3 = (pi*r^2)/2 = (3.14*2^2)/2 = 6.28 Ft^2 = area of semi-circle.

    A1 + A2 = A3
    A2 = A3-A1 = 6.28 - 6 = 0.3 Ft^2.

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